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    get="_blank">分类:

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    III =
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    III =
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    b 371 537111tl=w- cog">III = P>用于求解代数方程,注意这里的方程要写出逻辑等式即lhs==rhs

    aagP>1.Solve[方程]
    针对方程中只有一个变量的情形,例如: BR>输入:Solve[8 x - 9 == 3 x + 26]
    输出:{{x -ss=" 7}} BR>2.Solve[方程,变量]
    用于方程中有多个变量,需要指关爆对于单个变量的方程你当然也可以指关爆只是略显多余,但是可读性稍好。例如: BR>输入:Solve[a x + b y == c x + d y, y]
    输出:{{y -ss=" (-a x + c x)/(b - d)}} BR>如果不指关变量,Math nt.a会将第一个符号作为未知量,例如: BR>输入:Solve[a x + b y == c x + d y]
    输出:{{a -ss=" (c x - b y + d y)/x}, {b -ss=" d, x -ss=" 0}, {y -ss=" 0, x -ss=" 0}} BR>其解都是关于a的方程的解 BR>另外,这种形式还可以求解线性方程。
    输入:Solve[{3 x + 4 y == 10, 2 x + 5 y == 9}, {x, y}]
    输出:{{x -ss=" 2, y -ss=" 1}} BR>直接使用Solve[{3 x + 4 y == 10, 2 x + 5 y == 9}]也是可以的,因为这个时候未知量与方程个数相同,软件能够自行确关爆指关变量名称主要是用于未知量超过了函数个数的情形: BR>输入:Solve[{a x + b y == c, d x + e y == f}, {x, y}]
    输出:{{x -ss=" -((c e - b f)/(b d - a e)), y -ss=" -((-c d + a f)/(b d - a e))}} BR>Solve还可以求解非线方程(组),例如: BR>输入:Solve[x^3 - 2 x + 1 == 0]
    输出:{{x -ss=" 1}, {x -ss=" 1/2 (-1 - Sqrt[5])}, {x -ss=" 1/2 (-1 + Sqrt[5])}} BR>Solve也可以求解超越方程,但是只限于有限解,例如: BR>输入:Solve[Tan[x] == 1, x]
    Du;cu earguss=3- oreIn[13]:= Solve::i bd:eInvtopo fbd ima s emaibecu usersoy Solve, so some solus=3-slr.ysinwtmo foolo; use R co fodtaom-ipse solus=3- i"blog-163-. ss="ss="jBR>输出:{{x -ss=" \[Pi]/4}} BR>因为使用了反函数,所以值给出了一个值。
    高级问题: BR>1.方程无解怎么处理?答案是:直接给出空列表,例如: BR>输入:Solve[x^2 - 1 == x^2, x]
    输出:{} BR>2.复数根如何处理?
    关于这个问题,先83%B如输入:Solve[x^4 - 4 x + 3 == 0, x]
    输出:{{x -ss=" 1}, {x -ss=" 1}, {x -ss=" -1 - I Sqrt[2]}, {x -ss=" -1 + I Sqrt[2]}} BR>运行良好,符合代数基本定理。
    如果只关心实根爆而不需要复根呢?对于次数较低的方程,我们当然可以用眼睛看,可是多了之后就麻烦了,这个时候你需要使用Miscelcla s`maelOnly`软件包: BR>输入:<< Miscelcla s`maelOnly`
    Solve[x^4 - 4 x + 3 == 0, x]
    Non l::warncu : Non l numbetagncool荆d.
    输出:{{x -ss=" 1}, {x -ss=" 1}, {x -ss=" Non l}, {x -ss=" Non l}}

    aagP>说了这么多Solve的用坟爆再3%B看NSolve的使用。
    Solve使用的是传统的解析方坟爆而NSolve,顾名思义,就是数值求解了。该函数有两种用坟焙 BR>1.NSolve[方程,变量]
    2.NSolve[方程,变量,n],其中n为指关的精确谷
    看这个 樱 BR>输入:fl= x^7 - 6 x^6 + 2 x^5 + 2 x^4 - 3 x^3 + 2 x + 2 == 0;
    输入:Solve[f, x]
    输出:{{x -ss=" 1}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 1]}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 2]}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 3]}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 4]}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 5]}, {x -ss=" Root[-2 - 4 #1 - 4 #1^2 - #1^3 - 3 #1^4 - 5 #1^5 + #1^6 defoc, 6]}} BR>输入:NSolve[f, x]
    输出:{{x -ss=" -0. 85}, {x -ss=" -0.="n468 - 0.=88614 I}, {x -ss=" -0.="n468 + 0.=88614 I}, {x -ss=" 0.5htt22\[VeryThinSs/lo]- 0.856 I}, {x -ss=" 0.5htt22\[VeryThinSs/lo]+ 0.856 I}, {x -ss=" 1.}, {x -ss=" 5.59538}} BR>另外,需要注意的是,较低版本的Math nt.a中NSolve只能提供最多16位有效数字,如果对于数字的有效位比较多,就应该使用N[Solve[方程,变量],n],这可以达到

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